document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188333>Question 1188333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Without using tables, show that log base 10 of 17 is approximately equal to (2log base 10 of 6 + 3log base 10 of 2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819406 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Without using tables, show that log base 10 of 17 is approximately equal to (2log base 10 of 6 + 3log base 10 of 2).<BR>\n" );
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document.write( "log(17) = ~1.23<BR>\n" );
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document.write( "(2log base 10 of 6 + 3log base 10 of 2).<BR>\n" );
document.write( "2log(6) + 3log(2) = log(36) + log(8) = log(288) = ~2.459<BR>\n" );
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document.write( "\"Approximately\" can be a matter of opinion.<BR>\n" );
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document.write( "PS  No tables were used.  I used a calculator, a desk and a chair. </SPAN>\n" );
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