document.write( "Question 1188243: In the diagram below, Line BD=6 cm and Line DC=2 cm. Find the ratio of the area of the parallelogram to the area of Triangle ABC\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Diagram: https://imgur.com/a/mD01Rx2 \n" ); document.write( "

Algebra.Com's Answer #819309 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Draw a line perpendicular to BD from E.  Call this h.\r
\n" );
document.write( "\n" );
document.write( "Area of parallelogram is |CD|*h = 2h
\n" );
document.write( "Area of triangle BDE = (1/2)|BD|*h = 3h\r
\n" );
document.write( "\n" );
document.write( "Triangle BDE is similar to triangle BCA.
\n" );
document.write( "(Area triangle BCA) =  * (Area triangle BDE)
\n" );
document.write( "where  k = |BC|/|BD| = (6+2)/6 = 8/6 = 4/3
\n" );
document.write( "thus   = 16/9  \r
\n" );
document.write( "\n" );
document.write( "Putting it all together:   
\n" );
document.write( "(Area parallelogram)/(Area triangle BCA) = 2h / (3h * 16/9) = 3/8 \n" );
document.write( "

\n" );