document.write( "Question 1188238: Justin had some cards. He gave Alan 1/10 of the cards and bought another 45
\n" ); document.write( "new cards. Then he used 1/3 of the new total number of cards and bought 40 new
\n" ); document.write( "cards. He had 160 cards in the end. How many cards did he have at first? \n" ); document.write( "

Algebra.Com's Answer #819305 by MathTherapy(10555) $\"\"$ $\"About$

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\n" ); document.write( "Justin had some cards. He gave Alan 1/10 of the cards and bought another 45
\n" ); document.write( "new cards. Then he used 1/3 of the new total number of cards and bought 40 new
\n" ); document.write( "cards. He had 160 cards in the end. How many cards did he have at first?
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He's WRONG! \r\n" );
document.write( "Correct answer: Original number he had: 150\r\n" );
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document.write( "Let original number be C\r\n" );
document.write( "After giving away  and buying another 45, he had  remaining\r\n" );
document.write( "After using  of remainder, and buying 40 new, he had  remaining\r\n" );
document.write( "As he ended up with 160 cards, we get: \r\n" );
document.write( "                                                           3C = 5(90) ------ Cross-multiplying\r\n" );
document.write( "                              Original number of cards, or \r\n" );
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document.write( "This could've also been done with ratios instead of fractions.\r\n" );
document.write( "If you detest fractions, then you could try that.

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