document.write( "Question 1188247: Triangle ABC is isosceles, with Line AB=AC, and Line BC=39 cm A square is inscribed in the triangle with edges 21 cm. Find the area of Triangle ADE\r
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Algebra.Com's Answer #819293 by MathLover1(20850)\"\" \"About 
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Triangles ADE and ABC are similar, and the similarity coefficient is \"21%2F39+=+7%2F13\".\r
\n" ); document.write( "\n" ); document.write( "Let \"h\" be the altitude of the triangle ADE; then the altitude of the triangle ABC is \"+%28h%2B21%29\" centimeters.\r
\n" ); document.write( "\n" ); document.write( "The ratio of altitudes is the same\r
\n" ); document.write( "\n" ); document.write( " \"h%2F%28h%2B21%29+=+7%2F13\"\r
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\n" ); document.write( "\n" ); document.write( "It gives \r
\n" ); document.write( "\n" ); document.write( " \"13h+=+7%2A%28h%2B21%29\"
\n" ); document.write( "\"13h+=+7h+%2B+7%2A21\"
\n" ); document.write( "\"13h+-+7h+=+147\"
\n" ); document.write( "\"6h+=+147\"
\n" ); document.write( " \"h+=+147%2F6\"
\n" ); document.write( "\"h=+24.5cm\"\r
\n" ); document.write( "\n" ); document.write( "Thus the height of the smaller triangle ADE is \"h=24.5cm\"; then the height of the larger triangle is \"h%2B21=24.5%2B21+=+45.5cm\"\r
\n" ); document.write( "\n" ); document.write( "Now you know the base of the triangle ADE \"DE+=21cm\" and its height of \"h=24.5cm\", t hen its area of the smaller triangle ADE is \r
\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29%2A21cm%2A24.5cm+=+257.2cm%5E2+\"\r
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