document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1188249>Question 1188249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the 10th term of a geometric sequence whose 5th term is 81 and whose <BR>\n" );
document.write( "ninth term is 16. \r<BR>\n" );
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document.write( "I solved it as <BR>\n" );
document.write( "16 = 81r⁵⁻¹<BR>\n" );
document.write( "16 = 81r⁴<BR>\n" );
document.write( "r = -2/3, 2/3\r<BR>\n" );
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document.write( "I used the positive value and did<BR>\n" );
document.write( "a₁₀= 81(2/3)⁶⁻¹<BR>\n" );
document.write( "a₁₀= 32/3\r<BR>\n" );
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document.write( "Is this correct? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819291 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first term is (1.5)^4*81=410.0625 or 410(1/16)<BR>\n" );
document.write( "The 10th term is 32/3, as you found.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "It works for r=-(2/3), only the 10th term is -32/3. a1 is the same.<BR>\n" );
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