document.write( "Question 1188236: Suppose the scores of students on an exam are Normally distributed with a mean of 436 and a standard deviation of 94. Then approximately 99.7% of the exam scores lie between the numbers and such that the mean is halfway between these two integers. \n" ); document.write( "
Algebra.Com's Answer #819263 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the mean is 436. \n" ); document.write( "the standard deviation is 94. \n" ); document.write( "to find the critical scores that have 99.7% of the area under the normal distribution curve between them, use this calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the results of using the referenced calculator are shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the scores that have 99.7% of the area under the normal distribution curve between them are 157.033 to 714.967.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the distance between them and the mean of 436 is plus or minus 278.967.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "theo \n" ); document.write( " |