document.write( "Question 1188233: Two consecutive odd number are chosen so that one third of the smaller exceed one seventh of the larger by 6.find the numbers. \n" ); document.write( "

Algebra.Com's Answer #819258 by math_helper(2461) $\"\"$ $\"About$

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document.write( "(1/3)n = (1/7)(n+2) + 6\r
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document.write( "n = 33, n+2 = 35\r
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document.write( "Check:
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document.write( "(1/3)n = (1/3)(33) = 11
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document.write( "and
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document.write( "(1/7)(n+2)+6 = (1/7)(35)+6 = 5+6 = 11  (ok) \n" );
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