document.write( "Question 1187180: Out of 300 people sampled, 195had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids \n" ); document.write( "
Algebra.Com's Answer #819222 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! p=195/300=0.65 \n" ); document.write( "95% half-interval for a proportion is z(0.975)*sqrt(p(1-p)/n) \n" ); document.write( "so this is 1.96*sqrt(0.65*0.35/300) \n" ); document.write( "=0.054 \n" ); document.write( "the interval is (0.596, 0.704) \n" ); document.write( " |