document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1187690>Question 1187690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when packaging a product, a manufacturer finds that one packet in twenty is unerweight. Determine the probabilities that in a box of 72 packets<BR>\n" );
document.write( "(a)two<BR>\n" );
document.write( "(b)less than four will be underweight </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819192 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p=0.05<BR>\n" );
document.write( "for exactly 2 it is 72C2*0.05^2*0.95^70=0.1763<BR>\n" );
document.write( "for fewer than 4, calculate 3, 2,1,0<BR>\n" );
document.write( "for 3 it is 0.2165<BR>\n" );
document.write( "for 1 it is 72C1*0.05*0.95^71=0.0943<BR>\n" );
document.write( "for 0 it is 0.95^72=0.0249<BR>\n" );
document.write( "Those 4 add to 0.5120<BR>\n" );
document.write( "on the calculator, use binomcdf(72,0.05,3) and get 0.5119. The difference is in rounding, since the exact answer to more decimal places is 0.51194967, which barely fails to meet the rounding criteria to 0.5120. </SPAN>\n" );
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