document.write( "Question 1187716: A study is conducted to estimate the mean completion time of a task to within 3 minutes 6 seconds of the population mean. Suppose completion time is normally distributed with a standard deviation of 9 minutes 3 seconds. What minimum sample size is required at the 90.9% confidence level?\r
\n" ); document.write( "\n" ); document.write( "You must use a critical z value rounded to two (2) decimal places.
\n" ); document.write( "Do not round other intermediate results. Report final answer as an integer.\r
\n" ); document.write( "\n" ); document.write( "Minimum sample size required =
\n" ); document.write( "

Algebra.Com's Answer #819177 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the standard deviation is 9 minutes 3 seconds.
\n" ); document.write( "you want the margin of error to be plus or minus 3 minutes 6 seconds.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "it probably makes sense to convert everything to seconds.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "standard deviation of 9 minutes 3 seconds is equal to 543 seconds.
\n" ); document.write( "margin of error of 3 minutes 6 seconds is equal to 186 seconds.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the formula for the standard error is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "s = standard deviation / square root of sample size.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "90.9% confidence level gives you a two tail alpha of 100 - 90.9 = 9.1% / 2 = 4.55% on each end of the confidence interval.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's equivalent to an area of .0455 on each end of the confidence interval.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that give you a critical z-score of plus or minus 1.690146137.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you could probably round that off to 1.69 but we'll keep it at full value from the calculator for now.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the z-score formula is z = (x -m) / s\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw mean
\n" ); document.write( "s is the standard error.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the standard error is equal to the standard deviation divided by the square root of the sample size.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since the standard deviation is equal to 543 seconds, then the standard error is equal to 543 / sqrt(sample size).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if we want the margin of error to be equal to 186 seconds, then (x - m) must be equal to 186.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the z-score formula becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.690146137 = 186 / (543 / sqrt(sample size).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "this is equivalent to:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.690146137 = 186 * sqrt(sample size) / 543,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for sqrt(sample size) to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sqrt(sample size) = 1.690146137 * 543 / 186.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sqrt(sample size) = 4.934136303.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "square both sides of that equation to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "sample size = 24.34570106.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "calculate the standard error using the square root of the sample size to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "standard error = 543 / 4.934136303 = 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "with that standard error, you should be able to calculate the margin of error to get what you wanted it to be.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the high side, z = (x - m) / s becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.690146137 = (x - m) / 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for (x - m) to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(x - m) = 186.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the low side, z = (x - m) / s becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.690146137 = (x - m) / 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for (x - m) to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(x - m) = -186.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "looks like the margin of error is exactly what you wanted.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "this margin or error should be the same regardless of what the mean is, as ong as the standard error is equal to 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "to see if that's true, pick any mean that looks reasonable and solve for the confidence interval.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "assume the mean is 5000 seconds.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the critical z-score formula becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.690146137 = (x - 5000) / 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 1.690146137 * 110.0496554 + 5000 = 5186.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's 186 greater than 5000.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the low side, the formula becomes:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1.690146137 = (x - 5000) / 110.0496554.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = -1.690146137 * 110.0496554 + 5000 = 4814\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5000 - 4814 = 186, which is what you wanted.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your solution is that the minimum sample size required is 24.34570106.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "round that the next highest integer to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the minimum sample size required is 25.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's what i get.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "theo\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );