document.write( "Question 1187717: Hi
\n" ); document.write( "Mark had 80% more money than Bob. Vicky had 40% less than Bob. Mark and Bob gave vicky some money in the ratio of 3;2 respectively. In the end vicky had twice as much money as before. Given that Mark had $144 more than vicky in the end how much money did each of them have at first.\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #819171 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Mark had 80% more money than Bob.
\n" ); document.write( "m = 1.8b
\n" ); document.write( " Vicky had 40% less than Bob.
\n" ); document.write( "v = .6b
\n" ); document.write( " Mark and Bob gave vicky some money in the ratio of 3;2 respectively.
\n" ); document.write( "let a = amt of money m and b gave to v
\n" ); document.write( "then their remaining amts:
\n" ); document.write( "m = m - .6a
\n" ); document.write( "b = b - .4a
\n" ); document.write( " In the end vicky had twice as much money as before.
\n" ); document.write( "2v = v + a
\n" ); document.write( "v - v = a
\n" ); document.write( "v = a
\n" ); document.write( " Given that Mark had $144 more than vicky in the end
\n" ); document.write( "v = a
\n" ); document.write( "m - .6v = 2v + 144
\n" ); document.write( "m - .6v - 2v = 144
\n" ); document.write( "m - 2.6v = 144
\n" ); document.write( " how much money did each of them have at first.
\n" ); document.write( "find b, replace m with 1.8b, replace v with .6b
\n" ); document.write( "1.8b - 2.6(.6b) = 144
\n" ); document.write( "1.8b - 1.56b = 144
\n" ); document.write( ".24b = 144
\n" ); document.write( " b = 144/.24
\n" ); document.write( " b = $600 amt the Bob had
\n" ); document.write( "then
\n" ); document.write( "m = 1.8 * 600
\n" ); document.write( "m = $1080 is Mark's amt originally
\n" ); document.write( "and
\n" ); document.write( "v = .6 * 600
\n" ); document.write( "v = $360 is Vicky's amt\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );