document.write( "Question 1188012: The average American man consumes 9.5 grams of sodium each day. Suppose that the sodium consumption of American men is normally distributed with a standard deviation of 0.9 grams. Suppose an American man is randomly chosen. Let X = the amount of sodium consumed. Round all numeric answers to 4 decimal places where possible.\r
\n" ); document.write( "\n" ); document.write( "a. What is the distribution of X? X ~ N(
\n" ); document.write( "9.5
\n" ); document.write( "Correct,
\n" ); document.write( ".9
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\n" ); document.write( "\n" ); document.write( "b. Find the probability that this American man consumes between 9.2 and 10.9 grams of sodium per day.
\n" ); document.write( ".5707
\n" ); document.write( "Correct \r
\n" ); document.write( "\n" ); document.write( "c. The middle 20% of American men consume between what two weights of sodium?
\n" ); document.write( "Low: \r
\n" ); document.write( "\n" ); document.write( "High:
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Algebra.Com's Answer #819168 by Boreal(15235)\"\" \"About 
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the middle 20% is between the 40th and 60th percentiles or z=-0.253 to z=+0.253
\n" ); document.write( "0.253=(x-mean)/sd for upper limit
\n" ); document.write( "0.253=(x-9.5)/0.9
\n" ); document.write( "0.2280=x-9.5
\n" ); document.write( "x=9.7280 gms upper limit. Symmetrical here so lower limit is 9.2720 gms.
\n" ); document.write( "(9.2720, 9.7280) gms
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