document.write( "Question 1187852: The diagram shows a vertical cross -section of a container in the form of invented cone of height 60cm and base radius 20cm. The circular base is held horizontal and uppermost. Water is pured into the container at a constant rate of 40cm^3/s.
\n" ); document.write( "i)show that, when the depth of water in the container is x cm, the volume in the container is (pie x^3)/27 cm^3
\n" ); document.write( "ii) find the rate of increase of x at the instant when x=2. \n" ); document.write( "

Algebra.Com's Answer #819164 by AnlytcPhil(1806) $\"\"$ $\"About$

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document.write( "Because of similar right triangles,\r\n" );
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document.write( "The formula for the volume of a cone is \r\n" );
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document.write( "Substituting  and ,\r\n" );
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ii) find the rate of increase of x at the instant when x=2.

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document.write( "Divide both sides by 4\r\n" );
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document.write( "Multiply both sides by \r\n" );
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document.write( "Answer: The water level is rising at the rate of 90/π or about 28.6 centimeters per second.\r\n" );
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document.write( "Edwin

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