document.write( "Question 1187994: \"can u pls. help me write the following exponential equations in logarithmic form?\" 1.7^x=49 2.6^-3=(1/126) 3.12^2=144 also this...find the value of the following logarithmic expressions. 1.log3 243 2.log6 (1/216) 3.log0.25 16 thank u so much for the help. \n" ); document.write( "
Algebra.Com's Answer #819149 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "I suspect the way you posted the problems misled the other tutors. Very probably the first set of three problems are these:

\n" ); document.write( "(1) \"7%5Ex=49\"

\n" ); document.write( "(2) \"6%5E%28-3%29=1%2F216\" <-- that one includes a typo -- you showed 1/126....

\n" ); document.write( "(3) \"12%5E2=144\"

\n" ); document.write( "To convert each of those to logarithmic form, all you need to remember is this:

\n" ); document.write( "THE LOGARITHM IS THE EXPONENT

\n" ); document.write( "(1) The exponent is x; obviously the base is 7 --> \"log (base 7) of 49 is x\" --> \"log%287%2C%2849%29%29=x\"

\n" ); document.write( "(2) The exponent is -3; the base is 6 --> \"log (base 6) of 1/216 is -3\" --> \"log%286%2C%281%2F216%29%29=-3\"

\n" ); document.write( "(3) The exponent is 2; the base is 12 --> \"log (base 12) of 144 is 2\" --> \"log%2812%2C%28144%29%29=2\"

\n" ); document.write( "For the other problems you again only need to remember the same thing.

\n" ); document.write( "(1) \"log%283%2C%28243%29%29=x\" --> \"log (base 3) of 243 is x\" --> THE LOGARITHM (x) IS THE EXPONENT --> \"3%5Ex=243\"

\n" ); document.write( "(2) \"log%286%2C%281%2F216%29%29=x\" --> \"log (base 6) of 1/216 is x\" --> THE LOGARITHM (x) IS THE EXPONENT --> \"6%5Ex=1%2F216\"

\n" ); document.write( "(3) \"log%280.25%2C%2816%29%29=x\" --> \"log base 0.25 of 16 is x\" --> THE LOGARITHM (x) IS THE EXPONENT --> \"0.25%5Ex=16\"

\n" ); document.write( "I leave it to you to find the values of x for those last three problems.

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