document.write( "Question 1188078: Suppose f varies directly as the square of m, and inversely as j. Also, if f=36 when m=2 and j=10. Find f, if m=4 and j=6. \n" ); document.write( "
Algebra.Com's Answer #819146 by Theo(13342)\"\" \"About 
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f varies directly as the square of m and inversely as j.\r
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\n" ); document.write( "\n" ); document.write( "if f = 36 when m = 2 and j = 10, find the value of f when m = 4 and j = 6.\r
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\n" ); document.write( "\n" ); document.write( "the formula is f = k * m^2 / j.\r
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\n" ); document.write( "\n" ); document.write( "when f = 36 and m = 2 and j = 10, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "36 = k * 2^2 / 10.\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get:\r
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\n" ); document.write( "\n" ); document.write( "k = 36 * 10 / 2^2 = 90.\r
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\n" ); document.write( "\n" ); document.write( "k is the constant of variation.
\n" ); document.write( "it does not change it's value in the equation, while all the other variables can change their value.\r
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\n" ); document.write( "\n" ); document.write( "when m = 4 and j = 6, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "f = k * m^2 / j becomes:\r
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\n" ); document.write( "\n" ); document.write( "f = 90 * 4^2 / 6.\r
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\n" ); document.write( "\n" ); document.write( "solve for f to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 240.\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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