document.write( "Question 1188068: P(x)=x^4-x^3-13x^2+x+12\r
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Algebra.Com's Answer #819131 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the graph of the equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "your table of value would probably look like this:\r
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\n" ); document.write( "\n" ); document.write( "when you draw the graph manually, you plot the points from the table of values and then sketch the graph by connecting the points.\r
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\n" ); document.write( "\n" ); document.write( "when the table of values changes from positive to negative, that means the graph is crossing the x-axis somewhere in between.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "when x = -4, the graph is positive.
\n" ); document.write( "when x = -3, the graph is 0.
\n" ); document.write( "when x = -2, the graph i negative.\r
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\n" ); document.write( "\n" ); document.write( "the graph is crossing the x-axis between x = -4 and x = -2.\r
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\n" ); document.write( "\n" ); document.write( "you create the table by analyzing the value of p(x) = y at different values of x.\r
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\n" ); document.write( "\n" ); document.write( "for example, at x = 1, P(x) = y = x^4 - x^3 - 13x^2 + x + 12 becomes 1^4 - 1^3 - 13 * 1^2 + 1 + 12 which becomes 1 - 1 - 13 + 1 + 12 = 0.\r
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\n" ); document.write( "\n" ); document.write( "this can be seen both on the graph and the table of values.\r
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\n" ); document.write( "the coordinate points on the graph are in (x,y) format.
\n" ); document.write( "for example, (1,0) means the value of x is 1 and the corresponding value of y is 0 when the value of x is equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo
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