document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112294>Question 112294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square support unit in a television is made with a side measuring 3 centimeters. A new model being designed for the upcoming year will have a larger square with a side measuring 3.2 centimeters. By how much will the area of the square be increased?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81912 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First find the area of the older television\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%283%29%5E2=3%2A3=9 ALIGN=MIDDLE  ALT=\"A=%283%29%5E2=3%2A3=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now find the area of the newer model\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%283.2%29%5E2=%283.2%29%2A%283.2%29=10.24 ALIGN=MIDDLE  ALT=\"A=%283.2%29%5E2=%283.2%29%2A%283.2%29=10.24\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the area of the TV increased from 9 to 10.24 sq cm. Now simply subtract 9 from 10.24 to get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10.24-9=1.24 ALIGN=MIDDLE  ALT=\"10.24-9=1.24\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the area of the television increased 1.24 sq cm </SPAN>\n" );
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