document.write( "Question 1188040: Cara wants to invest $16,000 in certificates of deposit (CDs). For tax purposes, she wants her total interest per year to be $900. She wants to put $1000 more in a 2-year CD than in a 1-year CD and invest the rest in a 3-year CD. How much money should she invest in each type of CD?
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document.write( "| Number of Years: 1 | 2 | 3 |
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document.write( "| ________________________|______|______|
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document.write( "| Rate of Interest: 3.0% | 5.0% | 6.0% |
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document.write( "|_________________________|______|______| \n" );
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Algebra.Com's Answer #819101 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "x = invested at 3%;\r\n" ); document.write( "\r\n" ); document.write( "(x+1000) = invested at 5%;\r\n" ); document.write( "\r\n" ); document.write( "the rest, (16000-x-(x+1000)) = 15000-2x invested at 6%.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The total 1-year interest \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 0.03x + 0.05(x+1000) + 0.06(15000-2x) = 900.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 0.03x + 0.05x + 50 + 900 - 0.12x = 900\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 0.03x + 0.05x - 0.12x = 900 - 50 - 900\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " -0.04x = -50\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |