document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2062>Question 2062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is an equation in quadratic form.<BR>\n" );
document.write( "I need to find all roots.\r<BR>\n" );
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document.write( "What are the steps.  I am unclear on how to substitute.\r<BR>\n" );
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document.write( "(3/n) - (7/(sqrt n)) - (6) = 0\r<BR>\n" );
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document.write( "I think that the answer is 1/9, but I am not sure if I substituted right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #819 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let m = 1/sqrt(n), so 1/n = m^2.<BR>\n" );
document.write( " Substitute into (3/n) - (7/(sqrt n)) - (6) = 0 we have\r<BR>\n" );
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document.write( " 3m^2 - 7m - 6 = 0,<BR>\n" );
document.write( " Factor: (3m + 2)(m -3) = 0<BR>\n" );
document.write( " So,m = 3 or m =-2/3 (negative, invalid)<BR>\n" );
document.write( " Hence, n = 1/m^2 = 1/9...Answer\r<BR>\n" );
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document.write( " Check: (3/n) - (7/(sqrt n)) - 6 = 27 -21 -6 = 0 (OK)\r<BR>\n" );
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document.write( " Kenny<BR>\n" );
document.write( " </SPAN>\n" );
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