document.write( "Question 1187931: p is jointly proportional to q and r and p = 12 when q = 8 and r = 3
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Algebra.Com's Answer #818949 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"p\"$ is jointly proportional to $\"q\"$ and $\"r\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"p=k%2Aqr\"$ where $\"k+\"$ is constant\r
\n" ); document.write( "\n" ); document.write( " $\"k=p%2F%28qr%29++\"$ \r
\n" ); document.write( "\n" ); document.write( "if $\"p+=+12+\"$ when $\"q+=+8+\"$ and $\"r+=+3\"$ , than\r
\n" ); document.write( "\n" ); document.write( " $\"k=12%2F%288%2A3%29\"$
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\n" ); document.write( " $\"k=12%2F24\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=1%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "and equation is\r
\n" ); document.write( "\n" ); document.write( " $\"p=%281%2F2%29qr+\"$ \r
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\n" ); document.write( "\n" ); document.write( "Constant: $\"1%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "Equation: $\"p=%281%2F2%29qr+\"$ \r
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