document.write( "Question 1187914: the roots of 2x^2 +3x-1=0 are alpha and beta. Find the values of alpha square -beta square\r
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Algebra.Com's Answer #818938 by MathLover1(20850)\"\" \"About 
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\"2x%5E2+%2B3x-1=0+\" are \"alpha+\"and \"beta\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29+\"......\"a=2\",\"b=3%2C+and+%7B%7B%7Bc=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2B-sqrt%283%5E2-4%2A2%28-1%29%29%29%2F%282%2A2%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2B-sqrt%289%2B8%29%29%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2B-sqrt%2817%29%29%2F4+\"\r
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\n" ); document.write( "\n" ); document.write( "=> \"alpha+=%28-3%2Bsqrt%2817%29%29%2F4+\" and \"beta=%28-3-sqrt%2817%29%29%2F4+\"\r
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\n" ); document.write( "\n" ); document.write( "Find the values of \"alpha%5E2+-beta%5E2\":\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%5E2+-beta%5E2=%28-3%2Bsqrt%2817%29%29%5E2%2F16+-%28-3-sqrt%2817%29%29%5E2%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%5E2+-beta%5E2=%2826+-+6+sqrt%2817%29%29%2F16+-%2826+%2B+6+sqrt%2817%29%29%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%5E2+-beta%5E2=%2826+-+6+sqrt%2817%29+-26+-+6+sqrt%2817%29%29%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%5E2+-beta%5E2=%28+-+12+sqrt%2817%29%29%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"alpha%5E2+-beta%5E2=-%283sqrt%2817%29%29%2F4\"\r
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