document.write( "Question 1187894: Could you please help me with this proof involving Similar triangles? \r
\n" ); document.write( "\n" ); document.write( "\"IMG-5468\"
\n" ); document.write( "

Algebra.Com's Answer #818910 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The corresponding angles of similar triangles are equal:\r
\n" ); document.write( "\n" ); document.write( "Angle PMK = Angle KLR (1)
\n" ); document.write( "Angle PKM = Angle KRL (2)
\n" ); document.write( "Angle KPM = Angle RKL (3)\r
\n" ); document.write( "\n" ); document.write( "Now you can conclude from (3) that KL || PQ (if the corresponding angles of two lines cut by a transversal are equal, then those two lines are parallel)\r
\n" ); document.write( "\n" ); document.write( "Angle 1 = angle PMK (alternate interior angles of parallel lines cut by a transversal are equal)\r
\n" ); document.write( "\n" ); document.write( "Angle 2 = angle KLR (corresponding angles of parallel lines cut by a transversal are equal)\r
\n" ); document.write( "\n" ); document.write( "Therefore angle 1 = angle 2 (by the above two statements and (1))\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );