document.write( "Question 1187818: An observer 9m. horizontally away from the tower observes its angle of elevation to be only one half as much as the angle of elevation of the same tower when he moves 5m. nearer towards the tower. How high is the tower? \n" ); document.write( "
Algebra.Com's Answer #818904 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "An observer 9 meters horizontally away from the tower observes its angle of elevation to be only one half
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\n" ); document.write( "\n" ); document.write( "            It is a good  Trigonometry problem,  and it deserves a detailed explanation.\r
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document.write( "Let h be the height of the tower.\r\n" );
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document.write( "First position is 9 meters from the tower.  In this position,\r\n" );
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document.write( "    tan(a) = \"h%2F9\",  where \"a\" is the angle of elevation in this position.    (1)\r\n" );
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document.write( "Next position is  (9-5) = 4 meters from the tower.  In this position,\r\n" );
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document.write( "    tan(b) = \"h%2F4\",  where \"b\" is the angle of elevation in this position.    (2)\r\n" );
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document.write( "We are given  b = 2a.  Hence,\r\n" );
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document.write( "    tan(b) = tan(2a) = (use the basic Trigonometry formula) = \"%282%2Atan%28a%29%29%2F%281-tan%5E2%28a%29%29\" = \r\n" );
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document.write( "           = \"%282%2A%28h%2F9%29%29%2F%281+-+%28h%2F9%29%5E2%29\" = (simplify) = \"%282%2Ah%2A81%29%2F%289%2A%2881-h%5E2%29%29\" = \"%282%2Ah%2A9%29%2F%2881-h%5E2%29\" = \"%2818h%29%2F%2881-h%5E2%29\".\r\n" );
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document.write( "Thus from (2) we have THIS EQUATION\r\n" );
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document.write( "    \"%2818h%29%2F%2881-h%5E2%29\" = \"h%2F4\".\r\n" );
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document.write( "Cancel common factor \"h\" in both sides; then cross-multiply to get\r\n" );
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document.write( "    18*4 = 81 - h^2\r\n" );
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document.write( "     72  = 81 - h^2\r\n" );
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document.write( "    h^2 = 81 - 72 = 9.\r\n" );
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document.write( "Hence,  h = \"sqrt%289%29\" = 3.\r\n" );
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document.write( "ANSWER.  The tower height is 3 meters.\r\n" );
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