document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112232>Question 112232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find each rate\r<BR>\n" );
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document.write( "240 pounds of fertilizer<BR>\n" );
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document.write( "      6 lawns </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81882 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we are given 240 lbs of fertilizer to use on 6 lawns, all we need to do is divide the amount of fertilizer by the number of lawns which it must be used on.\r<BR>\n" );
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document.write( "So that's 240/6\r<BR>\n" );
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document.write( "Which is 40.\r<BR>\n" );
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document.write( "So we are allowed 40 lbs of fertilizer per lawn.  Or 40/1 </SPAN>\n" );
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