document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112241>Question 112241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem.  3x-75x^3=0.  I should come up with 3 answers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81881 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have to factor this equation before we can solve for its values of x.\r<BR>\n" );
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document.write( "Since both terms in the problem have 3x as a common factor, we can factor it out on the side:\r<BR>\n" );
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document.write( "3x -75x^3 = 0<BR>\n" );
document.write( "3x(-25x + 1)\r<BR>\n" );
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document.write( "Now, we can use the bottoms up rule in order to get the equation into a reasonable form.\r<BR>\n" );
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document.write( "3x(x^2 - 25) = 0\r<BR>\n" );
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document.write( "This can be further factored to:<BR>\n" );
document.write( "3x(x + 5)(x - 5) = 0\r<BR>\n" );
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document.write( "Let's remember to finish the bottoms up:<BR>\n" );
document.write( "3x(5x + 1)(5x - 1) = 0\r<BR>\n" );
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document.write( "Nwe, we kow our first value of x is 0 because:<BR>\n" );
document.write( "3x = 0<BR>\n" );
document.write( "x = 0\r<BR>\n" );
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document.write( "And our second value comes from the next term:<BR>\n" );
document.write( "(5x + 1) = 0<BR>\n" );
document.write( "5x = -1<BR>\n" );
document.write( "x = -1/5\r<BR>\n" );
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document.write( "And our third term comes from the final term:<BR>\n" );
document.write( "(5x -1) = 0<BR>\n" );
document.write( "5x = 1<BR>\n" );
document.write( "x = 1/5 </SPAN>\n" );
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