document.write( "Question 1187745: Hi, I'm working on a word problem (I'm not sure if it's completely accurate to geometry)
\n" ); document.write( "but this is the word problem: Latoya has twice as many CD's as Kristen. Sherry has
\n" ); document.write( "12 more than Kristen. Together they have 96 CD's How many does each girl have?\r
\n" ); document.write( "\n" ); document.write( "I would appreciate a step by step way to solve this, I get the concept a little bit but it still has me stuck!\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance :)
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Algebra.Com's Answer #818752 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "let say Kristen has \"x\" CD's\r
\n" ); document.write( "\n" ); document.write( "if Latoya has \"twice\" as many CD's as Kristen, tha n Latoya has \"2x\" CD's\r
\n" ); document.write( "\n" ); document.write( "if Sherry has \"12\" more than Kristen, than Sherry has \"x%2B12\" CD's\r
\n" ); document.write( "\n" ); document.write( "if they together have \"96\" CD's, than\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2x%2B%28x%2B12%29=96\"............solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2x%2Bx%2B12=96\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=96-12\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=84\"\r
\n" ); document.write( "\n" ); document.write( "\"x=21\"\r
\n" ); document.write( "\n" ); document.write( "Kristen has \"21\" CD's
\n" ); document.write( "Latoya has \"2%2A21=42\" CD's
\n" ); document.write( "Sherry has \"21%2B12=33\" CD's
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