document.write( "Question 1187713: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
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document.write( "{5x+y<2\r
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document.write( "1. (-1,,0)
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document.write( "2. (0-1)
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document.write( "3. (2,3)
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document.write( "4. (-3,-3)
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document.write( "5. (-4,4) \n" );
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Algebra.Com's Answer #818736 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Take each (x,y) pair and plug the numbers into both of the given inequalities. If the resulting inequalities are both true, then the pair is a solution; if either inequality is not true, the pair is not a solution. \n" ); document.write( "You can do the work as easily as we can.... \n" ); document.write( "Here's one.... \n" ); document.write( "3. (2,3) \n" ); document.write( "x+y > -2 \n" ); document.write( "2+3 > -2 \n" ); document.write( "5 > -2 \n" ); document.write( "TRUE \n" ); document.write( "5x+y < 2 \n" ); document.write( "5(2)+3 < 2 \n" ); document.write( "10+3 < 2 \n" ); document.write( "13 < 2 \n" ); document.write( "FALSE \n" ); document.write( "ANSWER: The second inequality is not true for (2,3), so (2,3) is NOT a solution to the system of inequalities \n" ); document.write( " \n" ); document.write( " |