document.write( "Question 1187713: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
\n" ); document.write( "{5x+y<2\r
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\n" ); document.write( "\n" ); document.write( "1. (-1,,0)
\n" ); document.write( "2. (0-1)
\n" ); document.write( "3. (2,3)
\n" ); document.write( "4. (-3,-3)
\n" ); document.write( "5. (-4,4)
\n" ); document.write( "

Algebra.Com's Answer #818736 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Take each (x,y) pair and plug the numbers into both of the given inequalities. If the resulting inequalities are both true, then the pair is a solution; if either inequality is not true, the pair is not a solution.

\n" ); document.write( "You can do the work as easily as we can....

\n" ); document.write( "Here's one....

\n" ); document.write( "3. (2,3)

\n" ); document.write( "x+y > -2
\n" ); document.write( "2+3 > -2
\n" ); document.write( "5 > -2
\n" ); document.write( "TRUE

\n" ); document.write( "5x+y < 2
\n" ); document.write( "5(2)+3 < 2
\n" ); document.write( "10+3 < 2
\n" ); document.write( "13 < 2
\n" ); document.write( "FALSE

\n" ); document.write( "ANSWER: The second inequality is not true for (2,3), so (2,3) is NOT a solution to the system of inequalities

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