document.write( "Question 1187334: 4. You are planning to deposit $15,000 into a bank account at the end of each year for 5 years. The bank account earns 7.5% compounded annually. After the four years (i think you meant five), you plan to withdraw $10,000 and transfer the balance to an account that earns 6% interest per year compounded semiannually and will remain in the account for 3 years. How much will be in your account at the end of the 8 years? \n" ); document.write( "
Algebra.Com's Answer #818731 by Theo(13342)![]() ![]() You can put this solution on YOUR website! this lends itself to excel analysis. \n" ); document.write( "this is the output of my efforts there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i think you meant after the 5 years. \n" ); document.write( "i'll assume that's what you meant because 5 + 3 = 8. \n" ); document.write( "if it's not what i assumed, then please correct me and i'll try again.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's my excel analysis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for the first give year, you are depositing 15000 at the end of each year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 1, you have 0 * 1.075 + 15000 = 15000 \n" ); document.write( "at the end of year 2, you have 15000 * 1.075 + 15000 = 31125 \n" ); document.write( "at the end of year 5, you have 67093.83 * 1.075 + 5000 = 77125.87 \n" ); document.write( "you only have 5000 deposit because you withdraw 10000. \n" ); document.write( "15000 deposit minus 10000 withdrawal equals a net deposit of 5000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "77125.87 is the remaining balance in the account that is then transferred to the new account that is earning 6% a year compounded semi-annually.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 5.5, you have 77125.87 * 1.03 = 79439.64.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this ame procedure continue until, at the end of year 8, you have 89410.02 * 1.03 = 92092.32.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "92092.32 is what you have at the end of the 8th year.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |