document.write( "Question 1187491: An object accelerates from rest at 3 m/s2 to the right with a net force of 280 N. Calculate the mass of the object and the distance it travels in 5 seconds. \n" ); document.write( "
Algebra.Com's Answer #818721 by KMST(5328)\"\" \"About 
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You know the formulas \"F=m%2Aa\" and \"d=%281%2F2%29at%5E2\" for distance traveled accelerating from rest.
\n" ); document.write( "You do not need to memorize formulas, you just need to understand them and think with your own head.
\n" ); document.write( "\"F=m%2Aa\" <--> \"F%2Fa=m\" is intuitive.
\n" ); document.write( "If you need a lot more force to get the same acceleration for a car than for a baby carriage, it must be that the car is a lot heavier.
\n" ); document.write( "If you need 100 times the force, it must be 100 times heavier.
\n" ); document.write( "If the acceleration you achieve with the same force is a lot less for the car it's because its heavier.
\n" ); document.write( "Acceleration is the change in velocity per second (we can say velocity is speed, if we all go in the same direction).
\n" ); document.write( "We divide distance by time once to get speed, then divide again to get acceleration.
\n" ); document.write( "If it is \"3\"\"m%2Fs%5E2\" , starting from rest, the speed will be
\n" ); document.write( "3 m/s after 1 second
\n" ); document.write( "3 m/s + 3 m/s = 6 m/s after another second (2 seconds from the start)
\n" ); document.write( "9 m/s after 3 seconds
\n" ); document.write( "12 m/s after 4 seconds
\n" ); document.write( "15 m/s after 5 seconds
\n" ); document.write( " For a constant 15 m/s speed, the graph would look like this ,
\n" ); document.write( "and the distance traveled in 5 seconds would be the constant 15 m/s speed times the 5 second travel time.
\n" ); document.write( "That is the area of the rectangle between 0 and 5 seconds under the speed graph:
\n" ); document.write( "\"%28%2215+m+%2F+s%22%29%28%22+5+Seconds%22%29=75m\"
\n" ); document.write( "For a variable speed, the distance traveled is also the area under the speed curve.
\n" ); document.write( "For the problem that area is a triangle, half the rectangle, 37.5 m.
\n" ); document.write( "No formulas needed, but we can deduce them if we need them.
\n" ); document.write( "Accelerating from rest the \"velocity\" \"v\" is \"v=a%2At\" ;
\n" ); document.write( "the area of the rectangle would be time times that velocity \"at%5E2\",
\n" ); document.write( "and the distance traveled is half of that \"d=%281%2F2%29at%5E2\" .
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