document.write( "Question 1187680: The surface area of a sphere varies directly as the square of the radius. If the surface
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document.write( "area is 36𝜋 𝑖𝑛
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document.write( "2 when the radius is 3 inches, what is the surface area of the sphere with
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document.write( "a radius of 5 inches? \n" );
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Algebra.Com's Answer #818702 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the direct variation formula is y = k * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = r^2, the formula becomes y = k * r^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when r = 3 and y = 36 * pi, the formula becomes 36 * pi = k * 3^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 36 * pi = k * 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for k to get k = 36 * pi / 9 = 4 * pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now that you have the value of k, you can solve for y when r = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of y = k * r^2 becomes y = 4 * pi * 5^2 which becomes y = 4 * pi * 25 which becomes y = 100 * pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k, being the constant of variation, doesn't change, as long as you're dealint with the surface area of a sphere.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you look up the formula for the surface area of a sphere, you will find that the formula is y = 4 * pi * r^2, where y is the surface area of the sphere. \n" ); document.write( "4 * pi remains the same, regardless of the measure of the radius. \n" ); document.write( "it becomes the constant of variation in that formula.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |