document.write( "Question 1187683: A substance in a chemical reaction is used up at a rate that is proportional to the
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document.write( "amount of the substance present at any time. If ½ of the substance is used up in 2
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document.write( "hours, how much of the substance is left at the end of 2 hours and 30 minutes? \n" );
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Algebra.Com's Answer #818699 by ikleyn(52866) You can put this solution on YOUR website! . \n" ); document.write( "A substance in a chemical reaction is used up at a rate that is proportional to the \n" ); document.write( "amount of the substance present at any time. If ½ of the substance is used up in 2 \n" ); document.write( "hours, how much of the substance is left at the end of 2 hours and 30 minutes? \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Since the substance in a chemical reaction is used up at a rate that is proportional \r\n" ); document.write( "to the amount of the substance present at any time, we have classical exponential decay of the substance.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "We also are given that the half-life time of this substance decay is 2 hours.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Since 2 hours and 30 minutes is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved, answered and explained in all details.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |