document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112216>Question 112216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular swimming pool is 4ft longer than it is wide. It is surrounded by a deck 3ft wide. Find the dimensions of the pool if the area of the deck is 264ft^2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81867 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE POOL IS X(X+4)=(X^2+4X) FT^2<BR>\n" );
document.write( "ADDING THE DECK DIMENTIONS WE HAVE:<BR>\n" );
document.write( "(X+6)(X+10)-264=(X^2+4X) WITH THE DECK THE TOTAL DIMENTIONS ARE (X+6) & (X+10)<BR>\n" );
document.write( "X^2+16X+60-264=X^2+4X CANCELLING OUT THE X^2 TERMS WE HAVE:<BR>\n" );
document.write( "16X-4X=204 <BR>\n" );
document.write( "12X=204<BR>\n" );
document.write( "X=204/12<BR>\n" );
document.write( "X=17 FT. IS THE WIDTH OF THE POOL.<BR>\n" );
document.write( "THUS THE LENGTH IS 17+4=21 FT.<BR>\n" );
document.write( "AREA OF THE POOL:<BR>\n" );
document.write( "17*21=357 FT^2.<BR>\n" );
document.write( "AREA OF THE POOL PLUS THE DECK:<BR>\n" );
document.write( "(17+6)(21+6)=23*27=621 FT^2<BR>\n" );
document.write( "THE DIFFERENCE IN AREA IS:<BR>\n" );
document.write( "621-357=264 FT^2 WHICH IS THE AREA OF THE DECK.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );