document.write( "Question 1187617: Hi
\n" ); document.write( "A gold bar is first cut into 2 pieces in the ratio of 2:5 . The heavier piece is then cut into 2 pieces in the ratio of 5:6. The difference between the mass of the heaviest piece and lightest piece was 24 grams. What was the mass of the gold bar before it was cut.\r
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Algebra.Com's Answer #818624 by ikleyn(52818) $\"\"$ $\"About$

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\n" ); document.write( "A gold bar is first cut into 2 pieces in the ratio of 2:5 .
\n" ); document.write( "The heavier piece is then cut into 2 pieces in the ratio of 5:6.
\n" ); document.write( "The difference between the mass of the heaviest piece and lightest piece was 24 grams.
\n" ); document.write( "What was the mass of the gold bar before it was cut.
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document.write( "Let x be the mass of the gold bar before it was cut.\r\n" );
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document.write( "After the first cut we have the pieces of    and    masses.\r\n" );
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document.write( "After the second cut, the heavier piece of    is disintegrated into the parts of\r\n" );
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document.write( " =   and   =   of mass.\r\n" );
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document.write( "Of three pieces,   = ,    and  ,  the heaviest part \r\n" );
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document.write( "is  ,  while the lightest part is  .\r\n" );
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document.write( "The difference is   -  = ,  so\r\n" );
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document.write( "     = 24.\r\n" );
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document.write( "It gives  x =  = 3*77 = 231 grams.\r\n" );
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document.write( "ANSWER.  The mass of the gold bar was initially 231 grams.\r\n" );
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