document.write( "Question 1187597: Help
\n" ); document.write( "1/4 of Tommy’s stickers is equal to 2/3 of Charlie’s stickers. Tommy
\n" ); document.write( "has 25 more stickers than Charlie. How many stickers do they have
\n" ); document.write( "altogether?
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Algebra.Com's Answer #818615 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Help
\n" ); document.write( "1/4 of Tommy’s stickers is equal to 2/3 of Charlie’s stickers. Tommy
\n" ); document.write( "has 25 more stickers than Charlie. How many stickers do they have
\n" ); document.write( "altogether?
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Let number Tommy and Charlie have, be T, and C, respectively\r\n" );
document.write( "Then we get: \"matrix%282%2C3%2C+%281%2F4%29T%2C+%22=%22%2C+%282%2F3%29C%2C+T%2F4%2C+%22=%22%2C+2C%2F3%29\"\r\n" );
document.write( "                 8C = 3T ------ Cross-multiplying ----- eq (i)\r\n" );
document.write( "            Also, T = C + 25 ----- eq (ii)\r\n" );
document.write( "                 8C = 3(C + 25) ----- Substituting C + 25  for T in eq (i)\r\n" );
document.write( "            8C - 3C = 75\r\n" );
document.write( "                 5C = 75\r\n" );
document.write( "Number Charlie has, or \"matrix%281%2C5%2C+C%2C+%22=%22%2C+75%2F5%2C+%22=%22%2C+15%29\"\r\n" );
document.write( "                        \r\n" );
document.write( "                        T = 15 + 25 ------ Substituting 15 for C in eq (ii)\r\n" );
document.write( "  Number Tommy has, or \"matrix%281%2C3%2C+T%2C+%22=%22%2C+40%29\"\r\n" );
document.write( "Amount both have: 15 + 40 = 55
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