document.write( "Question 16767: How many ounces of 20% antifreeze solution must be mixed with 30 ounces of a 50% antifreeze solution to make a 40% antifreeze solution? I have no idea where to start on this. Please help \n" ); document.write( "

Algebra.Com's Answer #8186 by Earlsdon(6294) $\"\"$ $\"About$

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Think about this...You want to add x oz. of 20% AF solution to 30 oz. of 50% AF solution to make (30 + x) oz. of 40% AF solution.
\n" ); document.write( "You can set up the necessary equation from this description. But first, change the percents to their decimal equivalents. 20% = 0.2, 40% = 0.4, and 50% = 0.5\r
\n" ); document.write( "\n" ); document.write( " $\"0.2x+%2B+0.5%2830%29+=+%2830+%2B+x%29%280.4%29\"$ Simplify and solve for x.
\n" ); document.write( " $\"0.2x+%2B+15+=+12+%2B+0.4x\"$ Subtract 0.2x from both sides.
\n" ); document.write( " $\"15+=+12+%2B+0.2x\"$ Now subtract 12 from both sides.
\n" ); document.write( " $\"3+=+0.2x\"$ Finally, divide both sides by 0.2
\n" ); document.write( " $\"15+=+x\"$ \r
\n" ); document.write( "\n" ); document.write( "You need to add 15 oz. of 20% AF solution to the 30 oz. of 50% AF solution to make 45 oz. of 40% AF solution.
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