document.write( "Question 1187549: Suppose that someone made a hot pizza, right after taking it out of the oven it had the temperature of 110C°, we can only ingest it, without the risk of it burning us, when it have its temperature equivalent to 40°C. The temperature of the food decreases according to the function: f(t)= 120.2^( - 1.6t)+10, with t being minutes. Once ready, from how long can we ingest it without the risk of getting burned?
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Algebra.Com's Answer #818547 by ikleyn(52778)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Suppose that someone made a hot pizza, right after taking it out of the oven it had the temperature of 110C°, \n" ); document.write( "we can only ingest it, without the risk of it burning us, when it have its temperature equivalent to 40°C. \n" ); document.write( "The temperature of the food decreases according to the function: f(t)= 120.2^( - 1.6t)+10, with t being minutes. \n" ); document.write( "Once ready, from how long can we ingest it without the risk of getting burned? \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Write the equation as you read the problem\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 120*2^(-1.6t) + 10 = 40 degrees of Celsium\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify it step by step\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 120*2^(-1.6t) = 40 - 10\r\n" ); document.write( "\r\n" ); document.write( " 120*2^(-1.6t) = 30\r\n" ); document.write( "\r\n" ); document.write( " 2^(-1.6t) = 30/120\r\n" ); document.write( "\r\n" ); document.write( " 2^(-1.6t) = 1/4\r\n" ); document.write( "\r\n" ); document.write( " 2^(-1.6t) = 2^(-2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Since the exponents are equal and the bases are equal, we conclude that the degrees/(indexes) are equal\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " -1.6t = -2 \r\n" ); document.write( "\r\n" ); document.write( " t =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |