document.write( "Question 1187549: Suppose that someone made a hot pizza, right after taking it out of the oven it had the temperature of 110C°, we can only ingest it, without the risk of it burning us, when it have its temperature equivalent to 40°C. The temperature of the food decreases according to the function: f(t)= 120.2^( - 1.6t)+10, with t being minutes. Once ready, from how long can we ingest it without the risk of getting burned?
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Algebra.Com's Answer #818547 by ikleyn(52778)\"\" \"About 
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\n" ); document.write( "Suppose that someone made a hot pizza, right after taking it out of the oven it had the temperature of 110C°,
\n" ); document.write( "we can only ingest it, without the risk of it burning us, when it have its temperature equivalent to 40°C.
\n" ); document.write( "The temperature of the food decreases according to the function: f(t)= 120.2^( - 1.6t)+10, with t being minutes.
\n" ); document.write( "Once ready, from how long can we ingest it without the risk of getting burned?
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document.write( "Write the equation as you read the problem\r\n" );
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document.write( "    120*2^(-1.6t) + 10 = 40   degrees of Celsium\r\n" );
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document.write( "Simplify it step by step\r\n" );
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document.write( "    120*2^(-1.6t) = 40 - 10\r\n" );
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document.write( "    120*2^(-1.6t) =    30\r\n" );
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document.write( "    2^(-1.6t)     =    30/120\r\n" );
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document.write( "    2^(-1.6t)     =    1/4\r\n" );
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document.write( "    2^(-1.6t)     =    2^(-2)\r\n" );
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document.write( "Since the exponents are equal and the bases are equal, we conclude that the degrees/(indexes) are equal\r\n" );
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document.write( "       -1.6t      =     -2        \r\n" );
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document.write( "           t      =     \"%28-2%29%2F%28-1.6%29\" = \"2%2F1.6\" = 1.25 \r\n" );
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document.write( "ANSWER.  The customer should wait 1.25 minutes = 1 minute and 15 seconds.\r\n" );
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