document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112217>Question 112217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Drews age is 8 years less than 3 times Ginas age. Drews is 28 years old how old is Gina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81850 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Drew's age is eight years less than three times Gina's age:<BR>\n" );
document.write( "3G - 8 = D<BR>\n" );
document.write( "And if Drew's age is 28:<BR>\n" );
document.write( "3G - 8 = 28<BR>\n" );
document.write( "Now we can solve for G, the unknown variable.<BR>\n" );
document.write( "Subtract the negetive eight from both sides:<BR>\n" );
document.write( "3G -(-8) = 28 -(-8)<BR>\n" );
document.write( "3G = 36<BR>\n" );
document.write( "Now divide both sides by three:<BR>\n" );
document.write( "G = 12<BR>\n" );
document.write( "So Gina is twelve years old. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );