document.write( "Question 1187483: If Anne is 4 years older than Marie and the sum of the squares of their ages is 40. what are their individual ages? \n" ); document.write( "
Algebra.Com's Answer #818493 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Solving by trial and error is far easier than a formal algebraic solution. Simply look for a way to break 40 into the sum of two perfect squares. \n" ); document.write( "1+39? no \n" ); document.write( "4+36? YES \n" ); document.write( "The squares of their ages are 4 and 36; their ages are 2 and 6. 6 is 4 more than 2, so that solution works. \n" ); document.write( "But probably a formal algebraic solution was wanted.... \n" ); document.write( "Let x = Marie's age \n" ); document.write( "Then x+4 = Anne's age \n" ); document.write( "The sum of the squares of their ages is 40: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Obviously the negative solution for Marie's age makes no sense; so x=2. \n" ); document.write( "ANSWERS: Marie's age = x = 2; Anne's age = x+4 = 6 \n" ); document.write( " \n" ); document.write( " |