document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1187499>Question 1187499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the numerator of the fraction is one less than twice the denominator. If 3 is added to both numerator and denominator, the resulting fraction can be reduced to 3/2 what is the original fraction. <BR>\n" );
document.write( "please help me :(​\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #818471 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=818471\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = the denominator.<BR>\n" );
document.write( "then 2x - 1 = the numerator.<BR>\n" );
document.write( "your fraction is (2x - 1) / x.<BR>\n" );
document.write( "add 3 to both numerator and denominator to get:<BR>\n" );
document.write( "(2x + 2) / (x + 3) = 3/2<BR>\n" );
document.write( "multiply both sides of the equation by (x + 3) to get:3x<BR>\n" );
document.write( "2x + 2 = 3/2 * (x + 3)<BR>\n" );
document.write( "multiply both sides of the equation by 2 to get:<BR>\n" );
document.write( "4x + 4 = 3 * (x + 3)<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "4x + 4 = 3x + 9<BR>\n" );
document.write( "subtract 3x from both sides of the equation and subtract 4 from both sides of the equation to get:<BR>\n" );
document.write( "x = 5.\r<BR>\n" );
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document.write( "that should be your solution.<BR>\n" );
document.write( "confirm by replacing x in the original equation with 5 to get:<BR>\n" );
document.write( "(2x - 1) / x becomes:<BR>\n" );
document.write( "9 / 5<BR>\n" );
document.write( "add 3 to both numerator and denominator to get:<BR>\n" );
document.write( "12 / 8<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "3/2.\r<BR>\n" );
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document.write( "x = 5 checks out ok.<BR>\n" );
document.write( "your solution is that the original fraction is 9/5. </SPAN>\n" );
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