document.write( "Question 1187453: Please help me with this. foci (-2, 3) and (4, 3) b=4. This is only the problem the teacher gave us. This is all about ellipse
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Algebra.Com's Answer #818430 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Equation of the ellipse: \"+%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\" where \"h\" and \"k\" are the coordinates of the center, \"a\" is semimajor axis length, and \"b\" semiminor axis length\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "foci (\"-2\", \"3\") and (\"4\", \"3\")
\n" ); document.write( "\"b=4\"\r
\n" ); document.write( "\n" ); document.write( "the center is midpoint between foci, and its coordinates will be at (\"%28-2%2B4%29%2F2\",\"%283%2B3%29%2F2\")= (\"1\",\"3\")=>\"h=1\" and \"k=3\"\r
\n" ); document.write( "\n" ); document.write( "the distance between the foci is equal to \"2c\"
\n" ); document.write( "\"2c=sqrt%28%28-2-4%29%5E2%2B%283-3%29%5E2%29\"
\n" ); document.write( "\"2c=sqrt%2836%2B0%29\"
\n" ); document.write( "\"2c=sqrt%2836%29\"
\n" ); document.write( "\"2c=+6\"
\n" ); document.write( "\"c=+3\"\r
\n" ); document.write( "\n" ); document.write( "substitute it in equation of elipse\r
\n" ); document.write( "\n" ); document.write( "\"+%28x-1%29%5E2%2Fa%5E2%2B%28y-3%29%5E2%2F4%5E2=1\" \r
\n" ); document.write( "\n" ); document.write( "\"+%28x-1%29%5E2%2Fa%5E2%2B%28y-3%29%5E2%2F16=1\" .............use \"c\"and \"b\" to calculate \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2-b%5E2\"
\n" ); document.write( "\"a=sqrt%28c%5E2%2Bb%5E2%29\"
\n" ); document.write( "\"a=sqrt%283%5E2%2B4%5E2%29\"
\n" ); document.write( "\"a=sqrt%2825%29\"
\n" ); document.write( "\"a=5\"\r
\n" ); document.write( "\n" ); document.write( "and your equation is:\r
\n" ); document.write( "\n" ); document.write( " \"%28x-1%29%5E2%2F25%2B%28y-3%29%5E2%2F16=1\"\r
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