document.write( "Question 112192: What values for x must be excluded in the following fraction? x-3/(4x-5)(x+1) \n" ); document.write( "
Algebra.Com's Answer #81841 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-3%29%2F%284x%5E2-x-5%29\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2-x-5=0\" Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.\r
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\n" ); document.write( "\n" ); document.write( "\"%284x-5%29%28x%2B1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"4x-5=0\" or \"x%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2F4\" or \"x=-1\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are \"x=5%2F4\" or \"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"x=-1\" and \"x=5%2F4\" make the denominator equal to zero, this means we must exclude \"x=-1\" and \"x=5%2F4\" from our domain\r
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