document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1187429>Question 1187429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I am confused thank You.  \r<BR>\n" );
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document.write( "Check that the following expressions are equivalent using the values x = -2, -1, 0, 1, 2.<BR>\n" );
document.write( "(12x^2−27)/(3)  and  −(−2x+3)(2x+3)\r<BR>\n" );
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document.write( "Prove the equivalence of the two expressions in the previous question using algebraic manipulation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #818392 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=818392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Check that the following expressions are equivalent using the values x = -2, -1, 0, 1, 2.<BR>\n" );
document.write( "(12x^2−27)/(3)  and  −(−2x+3)(2x+3)<BR>\n" );
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document.write( "Sub the values for x.<BR>\n" );
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document.write( "For x = -2:<BR>\n" );
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document.write( "(12*(-2)^2 - 27)/3 = -(-2*-2 + 3)*(2*-2 +3)<BR>\n" );
document.write( "(12*4 - 27)/3 = -(4 + 3)*(-4 + 3)<BR>\n" );
document.write( "21/3 = -7*-1<BR>\n" );
document.write( "7 = 7<BR>\n" );
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document.write( "Do the same for the other values.<BR>\n" );
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document.write( "Prove the equivalence of the two expressions in the previous question using algebraic manipulation.<BR>\n" );
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document.write( "(12x^2−27)/(3)  and  −(−2x+3)(2x+3)<BR>\n" );
document.write( "4x^2 - 9 = (2x-3)*(2x+3)<BR>\n" );
document.write( "4x^2 - 9 = 4x^2 - 9<BR>\n" );
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