document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1187380>Question 1187380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the 2nd and 5th term of a geometric progression are -6 48 respectively, find the sum of the 5th first four terms<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #818330 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=818330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 terms apart have a ratio of -8 in a geometric progression so r=-2. If second term is -6, first term is 3.<BR>\n" );
document.write( "sum is a(1-r^n)/(1-r)<BR>\n" );
document.write( "S= 3((1-(-2)^4)/(1-(-2))<BR>\n" );
document.write( "=-45/3<BR>\n" );
document.write( "=-15<BR>\n" );
document.write( "the terms are 3, -6, 12, -24, 48<BR>\n" );
document.write( "That is the first five terms, and the sum of the first four is -15 </SPAN>\n" );
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