document.write( "Question 1187373: Kier is x years old and his sister Nancy is x^2 yrs. old. In 7 years, Nancy will be 1 year older than twice Kier’s age at that time. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #818319 by Theo(13342)\"\" \"About 
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x = kier's age now.
\n" ); document.write( "x^2 = nancy's age now.
\n" ); document.write( "in 7 years, nancy will be 1 year older than twice kier's age at that time.
\n" ); document.write( "equation for that is:
\n" ); document.write( "x^2 + 7 = 2 * (x + 7) + 1
\n" ); document.write( "simplify to get:
\n" ); document.write( "x^2 + 7 = 2x + 15
\n" ); document.write( "subtract 2x + 15 from both sides of the equation to get:
\n" ); document.write( "x^2 + 7 - 2x - 15 = 0
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "x^2 - 2x - 8 = 0
\n" ); document.write( "factor this quadratic equation to get:
\n" ); document.write( "(x + 2) * (x - 4) = 0
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = -2 or x = 4
\n" ); document.write( "x can't be negative, so x = 4.
\n" ); document.write( "that's kier's age now.
\n" ); document.write( "nancy's age now is x^2 = 4^2 = 16
\n" ); document.write( "in 7 years kier will be 11 and nancy will be 23.
\n" ); document.write( "23 = 2 * 11 + 1 = 22 + 1 = 23.
\n" ); document.write( "that says that, in 7 years, nancy will be 1 year older than twice kier's age then.
\n" ); document.write( "requirements of the problem have been satisfied.
\n" ); document.write( "solution is that kier is 4 years old now and nancy is 16.\r
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