document.write( "Question 1187314: The first term of an arithmetic progression is 12 and the sum of the first 16 terms is 282.
\n" ); document.write( "a) Find the common difference of this progression.
\n" ); document.write( "The first, fifth and nth term of this arithmetic progression are the first, second and third
\n" ); document.write( "term respectively of a geometric progression.
\n" ); document.write( "b) Find the common ratio of the geometric progression and the value of n.
\n" ); document.write( "

Algebra.Com's Answer #818257 by greenestamps(13198)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The first 16 terms are

\n" ); document.write( "a, a+d, a+2d, ..., a+14d, a+14d

\n" ); document.write( "Combining like terms, the sum of the first 16 terms is

\n" ); document.write( "16a + (1+2+3+...+14+15)d = 16a+120d

\n" ); document.write( "The first term is 12; the sum of the first 16 terms is 282:
\n" ); document.write( "16(12)+120d = 282
\n" ); document.write( "192+120d = 282
\n" ); document.write( "120d = 90
\n" ); document.write( "d = 3/4

\n" ); document.write( "ANSWER a): the common difference is 3/4

\n" ); document.write( "1st term: 12
\n" ); document.write( "5th term: 12+4(3/4) = 12+3 = 15

\n" ); document.write( "The 1st and 5th terms of the arithmetic progression are the 1st and second terms of a geometric progression.

\n" ); document.write( "common ratio: 15/12 = 5/4

\n" ); document.write( "3rd term in the geometric progression: 15(5/4) = 75/4 = 12+27/4 = 12+9d, which is the 10th term of the arithmetic progression.

\n" ); document.write( "The 3rd term of the geometric progression is the 10th term of the arithmetic progression.

\n" ); document.write( "ANSWER b): common ratio 3/4; n=10

\n" ); document.write( "
\n" ); document.write( "
\n" );