document.write( "Question 112137: two ships leave a harbor traveling on courses that have an angle of 120 degrees between them. if they each travel 515 miles how far apart are they (to the nearest mile)? \n" ); document.write( "
Algebra.Com's Answer #81824 by edjones(8007)\"\" \"About 
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If they both travel 515 miles we can construc an isocoles triangle with apex of 120 deg and 2 base angles of (180-120)/2=30 deg each.
\n" ); document.write( "The easiest way find the base is to construct a line from the apex perpendicular to the base. It bisects the apex and forms two right triangles.
\n" ); document.write( "hyp=515
\n" ); document.write( "cos(30)=adj/515
\n" ); document.write( "adj=515cos(30)=446
\n" ); document.write( "446*2=892 mi. To find the full base we multiply times 2.
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