document.write( "Question 112137: two ships leave a harbor traveling on courses that have an angle of 120 degrees between them. if they each travel 515 miles how far apart are they (to the nearest mile)? \n" ); document.write( "
Algebra.Com's Answer #81824 by edjones(8007)![]() ![]() You can put this solution on YOUR website! If they both travel 515 miles we can construc an isocoles triangle with apex of 120 deg and 2 base angles of (180-120)/2=30 deg each. \n" ); document.write( "The easiest way find the base is to construct a line from the apex perpendicular to the base. It bisects the apex and forms two right triangles. \n" ); document.write( "hyp=515 \n" ); document.write( "cos(30)=adj/515 \n" ); document.write( "adj=515cos(30)=446 \n" ); document.write( "446*2=892 mi. To find the full base we multiply times 2. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |