document.write( "Question 1187276: A geometric progression has first term a and common ratio r. The sum of the first three terms is 62 and the sum to infinity is 62.5. Find the value of a and the value of r. \n" ); document.write( "
Algebra.Com's Answer #818228 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Sum of first three terms: a(1+r+r^2) = 62 [1] \n" ); document.write( "Infinite sum: a(1+r+r^2+...) = 62.5 [2] \n" ); document.write( "Sum of terms starting with the 4th: ar^3(1+r+r^2+...) = 62.5-62 = .5 [3] \n" ); document.write( "Divide [3] by [2]: \n" ); document.write( "r^3 = .5/62.5 = 1/125 = (1/5)^3 \n" ); document.write( "r = 1/5 \n" ); document.write( "Substitute r=1/5 in [1] to find a: \n" ); document.write( "a(1+1/5+1/25) = 62 \n" ); document.write( "a(1.24) = 62 \n" ); document.write( "a = 62/1.24 = 50 \n" ); document.write( "ANSWERS: \n" ); document.write( "a = 50 \n" ); document.write( "r = 1/5 \n" ); document.write( " \n" ); document.write( " |