document.write( "Question 112136: One number exceeds another by 5. One-fifth of their sum is five less than the smaller number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #81818 by bucky(2189)\"\" \"About 
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The first sentence says that \"one number exceeds another ...\" This statement tells you that
\n" ); document.write( "there are two unknown numbers. Call one of them x and the other y. Since one number
\n" ); document.write( "exceeds the other by 5, you know that if you take 5 away from one of the numbers, the result
\n" ); document.write( "equals the other number. In equation form this can be written as:
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\n" ); document.write( "\"x+-+5+=+y\" <=== call this your first equation
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\n" ); document.write( "In the next sentence the term \"of their sum\" tells you that you need to add the two numbers.
\n" ); document.write( "Their sum is written as \"x+%2B+y\". Then you need one-fifth of that sum, so you need to
\n" ); document.write( "multiply the sum by one-fifth. In algebraic form this is:
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\n" ); document.write( "\"%281%2F5%29%28x+%2B+y%29\" <=== refer to this as the \"algebraic form\"
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\n" ); document.write( "Finally you are told that this is algebraic form is 5 less than the smaller number.
\n" ); document.write( "This means that if you add 5 to this algebraic form the result will equal the smaller
\n" ); document.write( "number. From your first equation you can see that y is the smaller of the two numbers
\n" ); document.write( "because you have to take 5 away from x to get y. So add 5 to the algebraic
\n" ); document.write( "form and the result will equal y. In equation form this is written as:
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\n" ); document.write( "\"%281%2F5%29%28x+%2B+y%29+%2B+5+=+y\" <=== call this your second equation
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\n" ); document.write( "You now have two independent equations, each with two unknowns. Since there is a match between
\n" ); document.write( "the number of equations and the number of unknowns (and the equations are independent
\n" ); document.write( "of each other) you can solve for each unknown. Your first equation gives you a value for y
\n" ); document.write( "in terms of the second unknown ... which is x. You can see that y is equal to x minus 5.
\n" ); document.write( "Therefore, you can go to your second equation and in it you can replace y with x - 5. (This
\n" ); document.write( "method is referred to as solving the two equations by \"substitution.\") When you do this
\n" ); document.write( "substitution, the second equation becomes:
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\n" ); document.write( "\"%281%2F5%29%28x+%2B+%28x+-+5%29%29+%2B+5+=+x+-+5\"
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\n" ); document.write( "On the left side the quantity (x + (x - 5)) can be simplified. Since the set of parentheses
\n" ); document.write( "that contains x - 5 is preceded by a plus sign these parentheses can be removed without
\n" ); document.write( "changing the signs of the x and the -5 inside. This leaves you with (x + x - 5) and when
\n" ); document.write( "you add the x + x you end up with (2x - 5). Don't forget that this quantity has to be
\n" ); document.write( "multiplied by one-fifth, so you now have reduced the left side and the equation is:
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\n" ); document.write( "\"%281%2F5%29%282x+-+5%29%29+%2B+5+=+x+-+5\"
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\n" ); document.write( "You can now get rid of the \"1%2F5\" by multiplying both sides of this equation (all terms)
\n" ); document.write( "by 5. When you do this multiplication you get:
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\n" ); document.write( "\"2x+-+5+%2B+25+=+5x+-+25\"
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\n" ); document.write( "This multiplication makes it a little easier because you don't have to mess with fractions.
\n" ); document.write( "On the left side combine the two numbers -5 and + 25 to get +20 and the equation then is:
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\n" ); document.write( "\"2x+%2B+20+=+5x+-+25\"
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\n" ); document.write( "Let's get rid of the 2x on the left side by subtracting 2x from both sides. When you do
\n" ); document.write( "you get:
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\n" ); document.write( "\"+20+=+3x+-+25\"
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\n" ); document.write( "Then get rid of the -25 on the right side by adding 25 to both sides to get:
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\n" ); document.write( "\"45+=+3x\"
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\n" ); document.write( "You can solve for x by dividing both sides by 3 and the result is:
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\n" ); document.write( "\"15+=+x\"
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\n" ); document.write( "You now know that x equals 15 and your very first equation told you that if you take 5
\n" ); document.write( "away from x the result is y. Therefore, y equals 15 - 5 = 10.
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\n" ); document.write( "So the answer to this problem is x = 15 and y = 10.
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\n" ); document.write( "You can check the answer by returning to the two original equations, substituting
\n" ); document.write( "15 for x and 10 for y, and then simplifying to ensure that the left side of the equation
\n" ); document.write( "equals the right side.
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\n" ); document.write( "Return to the first equation and when you substitute 15 for x and 10 for y you have:
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\n" ); document.write( "15 - 5 = 10
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\n" ); document.write( "That reduces to:
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\n" ); document.write( "10 = 10
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\n" ); document.write( "so that works.
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\n" ); document.write( "Then go to the second equation and again substitute 15 for x and 10 for y to get:
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\n" ); document.write( "\"%281%2F5%29%2815+%2B+10%29%2B5+=+10\"
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\n" ); document.write( "Inside the parentheses on the left side the 15 + 10 becomes 25 ... so the equation
\n" ); document.write( "reduces to:
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\n" ); document.write( "\"%281%2F5%29%2825%29%2B5+=+10\"
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\n" ); document.write( "and one-fifth of 25 is 5 so the equation reduces to:
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\n" ); document.write( "\"5+%2B+5+=+10\"
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\n" ); document.write( "which simplifies to
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\n" ); document.write( "\"10+=+10\"
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\n" ); document.write( "Both your first and second equations work out if x = 15 and y = 10. Therefore, your answers
\n" ); document.write( "are correct.
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\n" ); document.write( "Hope this helps you to understand the problem and see how it can be worked out to get
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