document.write( "Question 1187243: y=-5/3x-1
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document.write( "y=x+7\r
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document.write( "Its asking to solve equation by graphing, then it ask for
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document.write( "X=?
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document.write( "Y=?
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Algebra.Com's Answer #818177 by Theo(13342)![]() ![]() You can put this solution on YOUR website! here's the graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the intersection point is at (x,y) = (12,19).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that means y = 19 when x = 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you solve algebraically, you should get the same answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "algebraically, you would do the following:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the two equatons that need to be solved simultaneously are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=-5/3x-1 \n" ); document.write( "y=x+7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since they are both equal to y, then 5/3 * x - 1 must be equal to x + 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5/3 * x - 1 = x + 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract x from both sides of the equation and add 1 to both sides of the equation t0 get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5/3 * x - x = 7 + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 * x - 3 * x = 3 * (7 + 1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms and simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2*x = 24.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 24/2 = 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x in both original equations to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=-5/3x-1 becomes y = 5/3 * 12 - 1 = 20 - 1 = 19. \n" ); document.write( "y=x+7 becomes y = 12 + 7 = 19.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the value of x is 12 in both equations and the value of y = 19 in both equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both equations have been solved simultaneously by the value of x = 12 and y = 19.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graphical solution provided the same answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's because x = 12 when y = 19 is common to both equations which means it's also common to both lines on the graph created by those equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |