document.write( "Question 112136: One number exceeds another by 5. One-fifth of their sum is five less than the smaller number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #81817 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=smaller number\r \n" ); document.write( "\n" ); document.write( "Then x+5=larger number\r \n" ); document.write( "\n" ); document.write( "Now we are told the following:\r \n" ); document.write( "\n" ); document.write( "1/5(x+x+5)=x-5 multiply each side by 5\r \n" ); document.write( "\n" ); document.write( "x+x+5=5x-25 subtract 5x and also 5 from both sides\r \n" ); document.write( "\n" ); document.write( "x+x+5-5-5x=5x-5x-25-5 collect like terms\r \n" ); document.write( "\n" ); document.write( "-3x=-30 divide both sides by -3 \n" ); document.write( "x=10-----------------------smaller number\r \n" ); document.write( "\n" ); document.write( "x+5=10+5=15 ---------larger number\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "1/5(10+15)=10-5\r \n" ); document.write( "\n" ); document.write( "1/5(25)=10-5 \n" ); document.write( "5=5\r \n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( " |